A particle moves in one dimension, and it\'s position as a function of time is g

Question

A particle moves in one dimension, and it's position as a function of time is given by x= (1.9m/s)t + (-3.0m/s^2)t^2
A) what is the particles average velocity from t=0.45s to t=.55s (indicate the direction with the sign of your answer)
B) what is the particles average velocity from t=.49s to t=.51s A particle moves in one dimension, and it's position as a function of time is given by x= (1.9m/s)t + (-3.0m/s^2)t^2
A) what is the particles average velocity from t=0.45s to t=.55s (indicate the direction with the sign of your answer)
B) what is the particles average velocity from t=.49s to t=.51s
A) what is the particles average velocity from t=0.45s to t=.55s (indicate the direction with the sign of your answer)
B) what is the particles average velocity from t=.49s to t=.51s

Explanation / Answer

x= 1.9t - 3 t^2

(A) average velocity = displacement / time

displacement = x(0.55) - x(0.45)

= 1.9(0.55 - 0.45) - 3(0.55^2 - 0.45^2)

= - 0.11 m

t = 0.55 - 0.45 = 0.1 s

<V> = - 0.11 / 0.1 = - 1.1 m/s .....Ans

(b) displacement = 1.9(0.51 - 0.49) - 3(0.51^2 - 0.49^2)

= - 0.022 m

t = 0.51 - 0.49 = 0.02 s

<v> = - 0.022/ 0.02 = - 1.1 m/s .......Ans

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