A particle moves in one dimension, and its position as a function of time is giv

Question

A particle moves in one dimension, and its position as a function of time is given by

x = (2.2 m/s)t + (?2.8 m/s2)t2.

(a) What is the particle's average velocity from t = 0.45 s to t = 0.55 s? (Indicate the direction with the sign of your answer.)

Average velocity is the change in position over change in time. Think about how to use the function to find the change in position. m/s

(b) What is the particle's average velocity from t = 0.49 s to t = 0.51 s? (Indicate the direction with the sign of your answer.)

Average velocity is the change in position over change in time. Think about how to use the function to find the change in position. m/s

Supporting Materials

Explanation / Answer

a) average v = deltax/delta t = ( (2.2*0.55 - 2.8*0.55^2)-(2.2*0.45 - 2.8*0.45^2))/(0.55-0.45)= -0.6 m/s

b) average v = ( (2.2*0.51 - 2.8*0.51^2)-(2.2*0.49 - 2.8*0.49^2))/(0.51-0.49) = -0.6 m/s

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