A particle moves in one-dimensional motion through a field for which the potenti

Question

A particle moves in one-dimensional motion through a field for which the potential energy of the particle-field system is as shown below, where A = 0.150 eV nm^3 and B = 3.68 ev nm. U(x)=A/x^3 - B/x The shape of this function is shown in the figure below. Find the equilibrium position x_0 of the particle. Enter a number differs from the correct answer by more than 10%. Double check your calculations, nm Determine the depth U_0 of this potential well. eV In moving along the * axis, what maximum force toward the negative * direction does the particle experience? nN

Explanation / Answer

1)

x0 = sqrt(A/B) = 0.35 nm

2)

depth = 7 ev

3)

force = m*du/dx

= m*(-3*A/x^4 + B/x^2)

but m is not given

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