A particle moves along the x axis. It is initially at the position 0.190 m, movi

Question

A particle moves along the x axis. It is initially at the position 0.190 m, moving with velocity 0.180 m/s and acceleration -0.260 m/s2. Suppose it moves with constant acceleration for 3.80 s. Find the position of the particle after this time. Your response differs from the correct answer by more than 10%. Double check your calculations, m Find its velocity at the end of this time interval. Next, assume it moves with simple harmonic motion for 3.80 s and x = 0 is its equilibrium position. (Assume that the velocity and acceleration is the same 3S in parts (a) and (b).) Find its position. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four Find its velocity at the end of this time interval.

Explanation / Answer

a)x=0.18*3.8-0.5*0.26*3.8^2=-1.19 final position=0.19-1.19=-1 m b)v=0.18-0.26*3.8=-0.808 m/s c)x=0.18*3.8-0.5*0.26*3.862=-1.19 x=-1.19 m d)v=0.18-0.26*3.8=-0.808 m/s

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