Heavy-duty AA alkaline dry cell\'s (+) terminal is 1.6 [V] higher than its (-) t

Question

Heavy-duty AA alkaline dry cell's (+) terminal is 1.6 [V] higher than its (-) terminal: they can deliver 1/16 [C/s] for 50 hours (180 ks) .. a) How much Energy does it start with? b) What Power production (in [Watt] !) will drain that battery in 50 hours? At this drain rate, the "terminal voltage" starts at 1.54[V], decreasing to 1.28 [V] after 25 hour and 1.02[V] after 50 hour. c) How much Energy does the user get from the battery?... how efficient is that discharge? (slower discharge terminal closer to 1.6V)

Explanation / Answer

A)

energy

E=VIt=1.6*(1/16)*(50*60*60)

E=18,000 J

b)

Power

P=E/t=18000/(50*60*60)=0.1 Watts

c)

Average Voltage

Vavg=1.54+1.28+1.02/3 =1.28 Volts

energy

E=(1/16)*1.28*(50*3600)=14,400 J

discharge is slower

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