1) if onion cells are isotonic to 0.5% NaCl solution. What will be happened if t
ID: 20813 • Letter: 1
Question
1) if onion cells are isotonic to 0.5% NaCl solution. What will be happened if the onion cells are placed in a 0.3% and 0.8% NaCl solutions?
2) In "Chardakov method for water potential measurement" experiment, you find that 0.30 M solution has not been changed by water loss or absorption by the potato in it. Determine the osmotic potential in Mpa of this solution (0.25 M = -5.75 Bars).
3) In Chardakov method for water potential measurment" experiment, once we cut the potato cylinders, why we have to place them in a covered beaker? (best guess please)
4)In the experiment "Osmosis: a specific diffusion of water passing a semi-permeable membrane ", how do you make 10 ml solution for each designed salt solutions (0, 0.625, 1.25, 2.5 and 10% salt solution) from a provided 10% salt solution) from a provided 10% salt solution?
5) When we measure the freezing point of potato sap, once the apparent freezing point of the potato sap appears, why does the temperature of the cell sap rise?
I would appreciate guesses and assumptions, don't be afraid of being wrong because you don't know the experiments in the class.
Thank you :)
Explanation / Answer
1.) 0.3% NaCl is Hypotonic to onion cells. so the osmotic potential difference causes flow of water from 0.3% NaCl to onion cells causing bulging of the cells. In the 0.8% NaCl water flows from onion cells to fluid and causes shrinkage of cells. this is based on difference in osmotic potentials
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