The mechanism shown in the figure (Figure 1) is used to raise a crate of supplie

Question

The mechanism shown in the figure (Figure 1) is used to raise a crate of supplies from a ship's hold. The crate has total mass 51kg . A rope is wrapped around a wooden cylinder that turns on a metal axle. The cylinder has radius 0.33m and a moment of inertia I = 3.0kg middot m2 about the axle. The crate is suspended from the free end of the rope. One end of the axle pivots on frictionless bearings: a crank handle is attached to the other end. When the crank is turned, the end of the handle rotates about the axle in a vertical circle of radius 0.12m , the cylinder turns, and the crate is raised. What magnitude of the force P applied tangentially to the rotating crank is required to raise the crate with an acceleration of 1.40 m/s2 ? (You can ignore the mass of the rope as well as the moments of inertia of the axle and the crank.) Express your answer using two significant figures. The mechanism shown in the figure (Figure 1) is used to raise a crate of supplies from a ship's hold. The crate has total mass 65kg. A rope is wrapped around a wooden cylinder that turns on a metal axle. The cylinder has radius 0.35m and a moment of inertia I = 2.2kg middot m2 about the axle. The crate is suspended from the free end of the rope. One end of the axle pivots on frictionless bearings; a crank handle is attached to the other end. When the crank is turned, the end of the handle rotates about the axle in a vertical circle of radius 0.12m , the cylinder turns, and the crate is raised. What magnitude of the force applied tangentially to the rotating crank is required to raise the crate with an acceleration of 1.40m/s2 ? (You can ignore the mass of the rope as well as the moments of inertia of the axle and the crank.) Express your answer using two significant figures.

Explanation / Answer

Force required to accelerate the crate

Fc= weight (mg) + accel. force (ma)

Fc = 51 kg x (9.80 + 1.40)m/s

= 571.2 N

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Torque atcylinderdue to crate,

Tc = Fc x r

= 571.2 N x 0.33m

= 188.49 Nm

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Torque required to accel. cylinder, T' = I.alpha

T' = 3.0 kg.m

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