An aluminum pot of mass 0.80 kg contains 1.2 liters of water. It is placed on th

Question

An aluminum pot of mass 0.80 kg contains 1.2 liters of water. It is placed on the burner of a gas range, and its temperature increases from 22.0 degrees C to 70.0 degrees C in a period of 5.5 minutes. Determine the rate at which heat is absorbed by the pot/water system, in watts. Assume the pot and water are always at the same temperature (that is, they are in thermal equilibrium with each other.) The specific heat capacity of aluminum is 234 J/(kg-K) and that of water is 4190 J/(kg-K). You don't have to worry about the fact that not all the heat from the flame is being absorbed: we only want the rate at which heat is absorbed by the pot of water.

Explanation / Answer

Q= Q1+Q2 = QAluminum +QWater=

(0.8 kg)(234 J/(kg*K))(48K) + (1.2 kg)(4190 J/(kg*K))(48K) = 8985.6 + 241344 =

250329.6 J

to convert J to W

250329.6 J / (5.5 min *60 sec) = 758.57

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.