A Proton between Oppositely Charged Plates A uniform electric field exists in th

Question

A Proton between Oppositely Charged Plates A uniform electric field exists in the region between two oppositely charged parallel plates 1.67 cm  apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time interval 1.54
A Proton between Oppositely Charged Plates A uniform electric field exists in the region between two oppositely charged parallel plates 1.67 cm  apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time interval 1.54 A Proton between Oppositely Charged Plates A uniform electric field exists in the region between two oppositely charged parallel plates 1.67 cm  apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time interval 1.54

Explanation / Answer

The el field E exerts a force, Fe = q.E on theproton, accelerates it to the -ve plate, at a distance, d = S = 1.67x10-2 m, in time t =1.54x10-6 s. FromS = ut + 0.5a.t2; u = 0 Acceleration, a =2S/t2 = 2x1.67x10-2/(1.54x10-6)2 = 1.40833x1010 m/s2 Acceleration, a =2S/t2 = 2x1.67x10-2/(1.54x10-6)2 = 1.40833x1010 m/s2 But, a = F/m = e.E/m Therefore, E =a.m/e =1.40833x1010x1.67x10-27/1.60x10-19 = 146.99 V/m (b) Velocity, v= u + at = at = 1.40833x1010x 1.54x10-6 = 2.168828x104m/s = 2.168828x104m/s

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