In the circuit below, a steady current Io is flowing when the switch is in posit

Question

In the circuit below, a steady current Io is flowing when the switch is in position a. If the switch is then thrown to position , the current will decrease to zero after some time.

Suppose we replace the inductor with one of the same area and length, but twice as many turns. The time required for current to drop to one-half its initial value, I(t) = 1/2Io

1. doubles.

2. increases by exp(2)

3. increases by 1/ln(2)

4. decreases by 1/ln(2)

5. increases by ln(2).

6. decreases by ln(2).

7. decreases by one-fourth

8. decreases by exp(2).

9. halves.

10. increases four-fold.

Explanation / Answer

inductance will increase by 4 times therefore timeconstant = L/R of the circuit will become 4 times

therefore timetaken for current to become I/2 will become four times

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