= Blocks A(mass6.50kg) and B(mass13.50kg) move on a frictionless, horizontal sur

Question

= Blocks A(mass6.50kg) and B(mass13.50kg) move on a frictionless, horizontal surface. Initially, block Bis at rest and block A is moving toward it at2.00m/s. The blocks are equipped with ideal spring bumpers. The collision is head-on, so all motion before and after the collision is along a straight line. Let + x be the direction of the initial motion of A. Find the maximum energy stored in the spring bumpers and the velocity of each block at that time. Find the maximum energy. Find the velocity of A. Find the velocity of B. Find the velocity of each block after they have moved apart. Find the velocity of A. Find the velocity of B.

Explanation / Answer

first the velocity of first block is maximum maximum compression occurs when velocity of both block are equal the the velocity of first block decreases and second block increases hence 6.5*2 =(6.5+13.5)v hence velocity of each block at that time v=0.65 m/s. hence energy stored is 1/2 6.5 *2^2 -1/2 *(6.5+13.5)*0.65^2 =8.775 J and final velocities ie velocity after complete sepration can be calculated by using elastic collision neglecting the spring..

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