A ball of circumference 70.1 cm and mass 625 g is forced to the bottom of a swim

Question

A ball of circumference 70.1 cm and mass 625 g is forced to the bottom of a swimming pool and then released. After initially accelerating upward, it rises at a constant velocity. (The density of water is 103 kg/m3.) (a) Calculate the buoyant force on the ball. (Indicate the direction with the sign of your answer.)
1
    (b) Calculate the drag force the ball experiences while it is moving upward at constant velocity. (Indicate the direction with the sign of your answer.) (a) Calculate the buoyant force on the ball. (Indicate the direction with the sign of your answer.)
1
    (b) Calculate the drag force the ball experiences while it is moving upward at constant velocity. (Indicate the direction with the sign of your answer.)

Explanation / Answer

Let the upward direction be positive

(a) Fb = Density of water * Volume of ball * g

=> Fb = 103 * (4/3)*pi*(0.701)^3 * 10 = 1486.21 N

(b) Fb - Drag force - mg =0 => - Drag = 1486.21 - (0.625*10)

=>Drag = - 1479.96 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.