E. Find the maximum acceleration of the mass. (in cm/s^2) Solution C)x= A sin(wt

Question

E.Find the maximum acceleration of the mass. (in cm/s^2)

Explanation / Answer

C)x= A sin(wt) v= Awcos(wt) => Aw = 20 cm/sec =>Also from graph w*0.4 = pi/2 => w = 3.92 rad/sec => A = 5.09 cm E) Maximum acceleration a = -Aw^2 sin(wt) => amax = Aw^2 = 78.29 rad/sec^2 F)Max acc occurs at wt = (2n+1)pi/2 => at n=0 , t = 0.4 sec [ acc = -78.29 rad/sec^2] =>at n=1 , t = 1.202 sec [ acc = 78.29 rad/sec^2] at these two points particle has max acc but opposite in direction G)w = sqrt(k/m) =>m = k/w^2 =4.62 kg Part D is not clear in the question itself it can be solved on the lines of part F

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