A block of massm=8.00{ kg}is attached to the end of an ideal spring. Due to the

Question

A block of massm=8.00{ kg}is attached to the end of an ideal spring. Due to the weight of the block, the block remains at rest when the spring is stretched a distanceh=9.00{ cm}from its equilibrium length. The spring has an unknown spring constantk. Take the acceleration due to gravity to beg=9.81{ m/s^2}. A.What is the spring constantk? Express your answer in newtons per meter. B. Suppose that the block gets bumped and undergoes a small vertical displacement. Find the resulting angular frequencyomegaof the block's oscillations about its equilibrium position.

Explanation / Answer

k*0.09 = 8*9.8 =>k = 871.11 N/m w = sqrt(k/m) =10.43 rad/sec

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