When a 0.20-kg is suspended from a vertically hanging spring, it stretches the s

Question

When a 0.20-kg is suspended from a vertically hanging spring, it stretches the spring from its original length of 0.040m to 0.045m. The same block is attached to the same spring and placed on a horizontal, frictionless surface as shown. The block is then pulled so that the spring stretches to a total length of 0.15m. The block is released at time t=0s and undergoes simple harmonic motion. Which one of the following expressions gives the displacement of the block as a function of time? Let x be in cm and t in seconds.

a) x = 15cos(14nt)
b) x = 15sin(14nt)
c) x = 44cos(14nt)

d) x = 7cos(15nt)
e) x = 14sin(15nt)

Explanation / Answer

A

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