A 3.5-kg block of iron (c=0.11 kcal/kg o C) that has been brought to a temperatu

Question

A 3.5-kg block of iron (c=0.11 kcal/kgoC) that has been brought to a temperature of 1,160oC is placed on top of a 2.6-kg block of ice (c=0.5 kcal/kgoC) that has been cooled to -50oC. Assuming no heat is lost to the surrounding container, what is the final temperature of the iron block? (Your answer should be given to the nearest oC.) A 3.5-kg block of iron (c=0.11 kcal/kgoC) that has been brought to a temperature of 1,160oC is placed on top of a 2.6-kg block of ice (c=0.5 kcal/kgoC) that has been cooled to -50oC. Assuming no heat is lost to the surrounding container, what is the final temperature of the iron block? (Your answer should be given to the nearest oC.)

Explanation / Answer

3.5*0.11*(1160-T)=2.6*0.5*50+2.6*80.16+2.6*1*T

So

T=58.02 deg Celcius

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