solve (i) and (ii). spam will be reported. The centre steel post B in the assemb

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solve (i) and (ii). spam will be reported.

The centre steel post B in the assembly below is 0.5 mm shorter than the aluminum posts A and C which have a length of 1 m. Post B has a cross-sectional area of 100 mm2 and is made of steel with an elastic modulus E = 200 GPa and yield stress sigma y = 280 MPa. Posts A and C each have a cross-sectional area of 50 mm2 and are made of aluminum with an elastic modulus E = 70 GPa and yield stress sigma y = 220 MPa. The steel plate on top is considered to be rigid. determine the force carried by each post give the total load that can be carried by this assembly Only image found

Explanation / Answer

1>sigma(Al)*l(Al)/E(Al)=sigma(steel)*l(steel)/E(steel)+.0005.....euation(1) sigma(Al)*2area(Al)+sigma(steel)*area(steel)=20kn*1......equation(2) put value we get sigma(Al),sigma(steel) sigma(Al)=78.88MPA sigma(steel)=121.16MPA FORCE ON EACH Al=78.88*10^6*50*10^-6=3944N FORCE ON STEEL=121.16*10012116.37N 2>TOTAL FORCE =2*220*50+280*100 50KN

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