solely as a function of conversion tor (i) a iow reactor and ir (21 aConstane ba

Question

solely as a function of conversion tor (i) a iow reactor and ir (21 aConstane batch reactor, The elementary reversible reaction P49, is carried out isothermally in a flow reactor with no pressure drop and where pure A is fed at a concentration of4.0 miol/dm3. If the equilibrium conversion is found to be 60% (a) What is the equilibrium constant, Kc, if the reaction occurs in the gas phase? (b) What is the Kc if the reaction is a liquid-phase reaction? P4-10o Consider the elementarv aas-nhace revercible reaetion is c -I

Explanation / Answer

kf[Ca0(1-xa)]2=kb[Ca0xa]

equilibrium constant kc=kf/kb

kc=[Ca0xa]/[Ca0(1-xa)]2

given Xa=0.6,Ca0=4

substitute you will get equilibrium constant in gas phase .We will not calculate Kcvalues in liquids and that value will be equal to one.please upvote to my answer and comment me ig your mind raised any quaries

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