A 2.0 kg block slides down a frictionless curved ramp, starting from rest at a h

Question

A 2.0 kg block slides down a frictionless curved ramp, starting from rest at a height of h = 1.0 m. The block then slides d = 8.0 m on a rough horizontal surface before coming to rest.

(a) What is the speed of the block at the bottom of the ramp?
          ______m/s

(b) What is the energy dissipated by friction?

          ______J

(c) What is the coefficient of friction between the block and the horizontal surface?
          ______

The answer to part a is 4.43 m/s, the answer to part b is 19.6 J, and the answer to part c is 0.125. I understand part a, but I am completely lost on parts b and c. Please include an explanation with your work and answer. I also may need to ask additional questions. Sorry for the low points; I'm running out.

Explanation / Answer

a.) 1/2mv^2 = mgh

v = 4.43m/s

b.) total intial energy = mgh = 19.62J

same amount of energy is disspated

c.) work done by friction = mu*mg*d = 19.62

mu = .125

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