Given that water at standard pressure freezes at 0 %u2218 C , which corresponds

Question

Given that water at standard pressure freezes at 0%u2218C, which corresponds to 32%u2218F, and that it boils at 100%u2218C, which corresponds to 212%u2218F, calculate the temperature difference %u0394T in degrees Fahrenheit that corresponds to a temperature difference of 1 K on the Kelvin scale. Give your answer to two significant figures What is the numerical value of the triple-point temperature Ttriple of water on the Rankine scale? Give your anwer to three significant figures.
Given that water at standard pressure freezes at 0%u2218C, which corresponds to 32%u2218F, and that it boils at 100%u2218C, which corresponds to 212%u2218F, calculate the temperature difference %u0394T in degrees Fahrenheit that corresponds to a temperature difference of 1 K on the Kelvin scale. Give your answer to two significant figures What is the numerical value of the triple-point temperature Ttriple of water on the Rankine scale? Give your anwer to three significant figures. What is the numerical value of the triple-point temperature Ttriple of water on the Rankine scale? Give your anwer to three significant figures.

Explanation / Answer

Temp change = F scale = 212 - 32 = 180 deg F

0 deg C = 0 +273 K = 273 K

100 deg C = 100 + 273 K = 373 K

Temperature change on Kelvin scale = 373 - 273 = 100 K

Thus, we get that temperature of 180 deg F is equivalent to 100 K.

Hence, difference of 1 K will lead to 1*100/180 = 0.56 deg F

Triple point of water = 273.16 K = 0 deg C

Using (F - 32) / 9 = C/5 we get

(F-32)/9 = 0/5

F = 32 deg

Thus Rankine temperature R = F+460 = 32+460 = 492 R

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