a 5kg (49n) brick is submerged in a pool of oil that starts at 100L, when it is

Question

a 5kg (49n) brick is submerged in a pool of oil that starts at 100L, when it is submerged it lays to rest on a scale at the bottom showing, 26.51N and the oil is now 102.5L.

What is the buoyant force acting on the brick? I assume (26.51) or is it 49-26.51=22.49N?

Now calculate the density of the fluid (oil) from the definition of the buoyant force. Show your work for full credit.

Does this calculated value agree with the expected density of oil 920kg/m^3

I believe the equation would be 1*9.8*2.5=22.49 or should the 22.49 be 26.51 then it wouldn't be close to 920 though. I need help Thanks. ALso what force is shown by the scale?

Explanation / Answer

buyont force = weight of liquid displaced = 22.49 N

22.49 = p*g*.0025

p = 917.959

yes it does agree

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