Reflection and Refraction Question: Red light is incident in air on a 30 degree
ID: 2120747 • Letter: R
Question
Reflection and Refraction Question:
Explanation / Answer
Call the bottom left of the prism A.
Call the entry point of the light ray B.
Call the exit point of the light ray C.
Drop a perpendicular from B to AC to meet AC at P
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1)
In triangle ABP:
tan(30) = h/AP
AP = 19/tan(30) = 32.91cm
In triangle PBC:
PC = AC - AP = 77.9 - 32.91 = 45 cm
tan(si2) = h/PC = 29/45 -= 0.644
si(2) = arctan(1.293) = 32.78
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2)
Angle ABC = 180 - 30 - 52.3 = 117.22
Draw the normal at point B
Mark the angle of refraction at B as beta.
beta = 117.22 - 90 = 17.22
From the diagram you should see:
The angle of incidence, alfa = 90 - 30 - (si)1 = 60 - 40.9 = 11.1
From Snell's law
Refractive index, u = sin(alfa)/sin(beta) = sin(11.1)/sin(17.22) = 0.65
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3) Find the angle of incidence in the glass at point C, then use Snell's law to find the angle of refraction in the air. Then find %u03C6%u2083
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4) Work out the critical angle in the glass. Then use this and geometry to work out the angle of refraction at point B. Then use Snell's law to work out the angle of incidence at point B. Then you can find %u03C6%u2081-max
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5) Can't do this without knowing the refractive index for violet light. If you have this information, you have to work-rthe calculations using the same methods as above.
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