A particle moving in the y-z plane with a velocity vector v? = ( 23 ?+ 16 ? ) m/

Question

A particle moving in the y-z plane with a velocity vector v? = ( 23 ?+ 16 ? ) m/s enters an electric field which gives it a constant acceleration. The acceleration vector is a? = ( -2 ? -7 ?) m/s2. Ignore the effects of gravity. When the particle returns to the same z-coordinate it had when it entered the electric field, how far will it be from the point at which it entered the electric field? The particle will be m from its point of entry into the electric field when it returns to the same z-coordinate. A particle moving in the y-z plane with a velocity vector v? = ( 23 ?+ 16 ? ) m/s enters an electric field which gives it a constant acceleration. The acceleration vector is a? = ( -2 ? -7 ?) m/s2. Ignore the effects of gravity. When the particle returns to the same z-coordinate it had when it entered the electric field, how far will it be from the point at which it entered the electric field? The particle will be m from its point of entry into the electric field when it returns to the same z-coordinate.

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where did you get 3.26 from?

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