A movig particle encounters an external electric field that decreases its kineti

Question

A movig particle encounters an external electric field that decreases its kinetic energy from 9810  eV to 6180 eV as the particle moves from position A to position B. The electric potential at A is -46.0  V, and that at B is +33.0  V. Determine the charge of the particle. Include the algebraic sign (+ or -) with your answer.

A movig particle encounters an external electric field that decreases its kinetic energy from 9810 eV to 6180 eV as the particle moves from position A to position B. The electric potential at A is -46.0 V, and that at B is +33.0 V. Determine the charge of the particle. Include the algebraic sign (+ or -) with your answer.

Explanation / Answer

q =(K1-K2)/(V2-V1)

q=(9810-6180)(1.6*10^-19)/(33-(-46))

q= +7.35*10^-18 C

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