a rod had a 1.3 m long section that is cast iron and a 2.6 m long section that i

Question

a rod had a 1.3 m long section that is cast iron and a 2.6 m long section that is aluminum. the diameter of the cylindrical rod is .40 cm. Ycast iron = 100x 10^10 N/m^2 and Yaluminum = 7x10^10 N/m^2. how much elongation is produced in the rod when it is subjected to a force of 4.1x10^3 N?

answer in cm

a rod had a 1.3 m long section that is cast iron and a 2.6 m long section that is aluminum. the diameter of the cylindrical rod is .40 cm. Ycast iron = 100 times 10^10 N/m^2 and Yaluminum = 7x10^10 N/m^2. how much elongation is produced in the rod when it is subjected to a force of 4.1 times 10^3 N?

Explanation / Answer

Y= F/A /dL/L

dL/L=F/AY

dL=FL/AY

dL=(4.1*10^3 /pi*0.002^2)*(1.3/100*10^10 +2.6/7*10^10)

dL=0.012543m

dL=1.254cm

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