A particle has a charge of +3.3 ?C and moves from point A to point B , a distanc

Question

A particle has a charge of +3.3 ?C and moves from point A to point B, a distance of 0.12 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +8.2 x 10-4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the electric field that the particle experiences.

(a) Number Units N/CkgCmN A particle has a charge of +3.3 ?C and moves from point A to point B, a distance of 0.12 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +8.2 x 10-4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the electric field that the particle experiences.

Explanation / Answer

B)2.07*10^3 N/C........

A))force F=q*E=3.3*10^-6*2.07*10^3=6.831*10^-3 N

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