Consider a car going down a roller coaster track like in the figure. If at the b

Question

Consider a car going down a roller coaster track like in the figure. If at the bottom position, the apparent weight of a passenger (i.e. the Normal force acting on the passenger)  is  3 times the real weight mg, what is the speed of the roller coaster? The radius of curvature is 20 m.

Answer

20 m/s

40 m/s

14 m/s

3.0 m/s

Please explian why!

20 m/s

40 m/s

14 m/s

3.0 m/s

Consider a car going down a roller coaster track like in the figure. If at the bottom position, the apparent weight of a passenger (i.e. the Normal force acting on the passenger) is 3 times the real weight mg, what is the speed of the roller coaster? The radius of curvature is 20 m.

Explanation / Answer

at the bottom N - mg = m*v^2/R 3mg - mg = mv^2/R v = sqrt(2*g*R) = 20m/s

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