A block with mass \\(m_{A} = 15.0kg\\) on a smooth horizontal surface is connect

Question

A block with mass (m_{A} = 15.0kg) on a smooth horizontal surface is connected by a thin cord that passes over a pulley to a second block with mass (m_{B} = 6.0kg) which hangs vertically. Determine the magnitude of the acceleration of the system? If initially (m_{A}) is at rest 1.250 m from the edge of the table, how long does it take to reach the edge of the table if the system is allowed to move freely? If (m_{B} = 1.0kg) , how large must (m_{A}) be if the acceleration of the system is to be kept at (1/100g) ?

Explanation / Answer

6*9.8-T=6*a

T=15*a

solving we get

accleration

a=2.8m/s/s

2) now S=1.25m

we know

S= u*t+0.5*a*t*t

where u =0

so t= 0.945sec

3)if mB=1kg

then

1*g-T=1*a

T=m*a

here a=g/100

solving we get

mA=99kg

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.