In the figure, two identical ideal massless springs have unstretched lengths of

Question

In the figure, two identical ideal massless springs have unstretched lengths of 0.25 m and spring constants of 700 N/m. The springs are attached to a small cube and stretched to a length L of 0.30 m as in Figure A. An external force P pulls the cube a distance D = 0.020 m to the right and holds it there. (See Figure B.) The external force P, that holds the cube in place in Figure B, is closest to

In the figure, two identical ideal massless springs have unstretched lengths of 0.25 m and spring constants of 700 N/m. The springs are attached to a small cube and stretched to a length L of 0.30 m as in Figure A. An external force P pulls the cube a distance D = 0.020 m to the right and holds it there. (See Figure B.) The external force P, that holds the cube in place in Figure B, is closest to

Explanation / Answer

Correct Answer: 28N

Given Hooke's Law, F=kx where F is spring force, k is the constant and x is the position.

with changing position this will be delta x.

And F on the left side is equal to F on the right side

Using the formula above, the right side is F=(700)(0.3+0.02-.25)=49N

For the right side, F=(700)(0.3-0.02-0.25)=21N

Since the force from the left side needs to equal the force from the right, find the difference between these two forces to find the outside force P: (49N-21N)=28N

So the answer is 28N

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