help A straight wire carrying a 2.76-A current is placed in a uniform magnetic f

Question

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A straight wire carrying a 2.76-A current is placed in a uniform magnetic field of magnitude 0.258 T directed perpendicular to the wire. Find the magnitude of the magnetic force on a section of the wire having a length of 13.9 cm. N Explain why you can't determine the direction of the magnetic force from the information given in the problem. This answer has not been graded yet. A wire carries a steady current of 2.20 A. A straight section of the wire is 0.750 m long and lies along the x axis within a uniform magnetic field, = 1.90 khat T. If the current is in the positive x direction, what is the magnetic force on the section of wire? Magnitude N Direction A rod of mass 0.720 kg and radius 6.00 cm rests on two parallel rails (see figure below) that are d = 12.0 cm apart and L = 45.0 cm long. The rod carries a current of I = 52.0 A in the direction shown and rolls along the rails without slipping. A uniform magnetic field of magnitude 0.310 T is directed perpendicular to the rod and the rails. If it starts from rest, what is the speed of the rod as it leaves the rails? (Assume that the rod is of uniform density.) m/s

Explanation / Answer

1)

a)

Force = BIl = 0.258*2.76*0.139 = 0.099 N

b)

as the direction of current is not known so we cant.

2)

F = BIl = 1.9*2.2*0.75 = 3.135 A

direction = -y axis

3)

So, F=BIl

So, torque, T = Ma/r = rF

So, a = Fr^2/M

v^2 = 2*a*s

So, v = sqrt(2*Fr^2*s/M) = sqrt(2*BIlr^2/M) = sqrt(12BIlr^2/md^2)

= sqrt(12*0.31*52*0.12*0.06^2/(0.72*0.12^2)) = 2.84 m/s <--------answer

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