help A series AC circuit contains a resistor, an inductor of 250 mH, a capacitor
ID: 2261094 • Letter: H
Question
help
A series AC circuit contains a resistor, an inductor of 250 mH, a capacitor of 5.30 mu F, and a source with Delta v max = 240 V operating at 50.0 Hz. The maximum current in the circuit is 140 mA. Calculate the inductive reactance. ohm Calculate the capacitive reactance. ohm Calculate the impedance. k ohm Calculate the resistance in the circuit. k. ohm Calculate the phase angle between the current and the source voltage. o A 44.0-.ohm resistor is connected in series with a 29.0-mu F capacitor and a source whose maximum voltage is 119 V, operating at 60.0 Hz. Find the capacitive reactance of the circuit. Find the impedance of the circuit. ohm Find the maximum current in the circuit. A Does the voltage lead or lag the current? The voltage leads the current. The voltage lags behind the current. How will adding an inductor in series with the existing resistor and capacitor affect the current? Explain.Explanation / Answer
A) inductive reactance XL=Lw=(250*10^-3)*2*pi*50=78.55 ohms..
B) capacitive reactance Xc=1/CW=600.5 ohms
C)impedence Z=E0/Io=1.71428 kohms
d)Z^2=R^2+(XL-Xc)^2...
R=1814.713 ohms=1.814 kohms
e)phi=tan^-1[XL-Xc/R]=-16.04 current leads voltage by 16.04 degrees
A) capacitive reactance Xc=1/CW=91.45 ohms
B)impedence Z=Emax/Imax=sqrt[R^2+Xc^2]=101.48 ohms
C)Z=Emax/Imax...
Imax=Emax/Z=1.172 A
D)the voltage lags behind the current.
E)when inductor is in circuit.....impedence is Z=sqrt[R^2+(XL-Xc)^2]
impedence decreases hence current increases........
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.