A 5 kg block is connected to a 1 kg block with a light, non-stretchy rope. The 1

Question

A 5 kg block is connected to a 1 kg block with a light, non-stretchy rope. The 1 kg block is placed on a table, and the coefficient of kinetic friction between the table and the block is 0.35. The 5 kg block is dangled off the edge of the table by passing the rope over a frictionless pulley. A second rope then is used to connect a 3 kg block to the 1 kg block. The 3 kg block is dangled from the other side of the table, again using a frictionless pulley. When everything is released, the 5 kg block falls. What is its acceleration?

Explanation / Answer

Let the tension on the rope joining the 5 kg block be T1 and that joining the 3 kg block be T2

5g-T1=5a 1)

For 1 kg block,

T1-T2-0.35*1*9.8=1a 2)

For 3 kg block,

T2-3g=3a 3)

Solving simultaneously,

T1=40N

T2=34.8N

a=1.8m/s2

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