Please answer A puck (mass m1 = 2.45 kg) slides on a frictionless table as shown

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A puck (mass m1 = 2.45 kg) slides on a frictionless table as shown in the figure below. The puck is tied to a string that runs through a hole in the table and is attached to a mass m2 = 7.4 kg. The mass m2 is initially at a height of ft = 7.4 m above the floor with the puck traveling in a circle of radius r = 1.96 m with a speed of 7.4 m/s. The force of gravity then causes mass m2 to move downward a distance 0.74 m. What is the new speed of the puck? What is the change in the kinetic energy of the puck? A bug of mass 2.8 g is sitting at the edge of a CD of radius 4.0 cm. If the CD is spinning at 210 rpm, what is the angular momentum of the bug?

Explanation / Answer

a) angular momentum conservation, (mvr)
m x 7.4 x 1.96 = m x v x (1.96 - 0.74)
v = 11.89 m/s

b) K.>e = 2.45 x (11.89^2 - 7.4^2)/2 =106.06 J

2. w = 210 rpm = 210 x 2pi rad / 60 sec =21.99 rad/sec
v = w.r
p = mvr = mwr^2 = 2.46 x 10-3

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