A 10 kg object has a moment of inertia of 1.25 kg m 2 . If a torque of 2.5 N A 1
ID: 2144878 • Letter: A
Question
A 10 kg object has a moment of inertia of 1.25 kg m2. If a torque of 2.5 N A 10 kg object has a moment of inertia of 1.25 kg m2. If a torque of 2.5 N A 10 kg object has a moment of inertia of 1.25 kg m2. If a torque of 2.5 N A 10 kg object has a moment of inertia of 1.25 kg m2. If a torque of 2.5 N m is applied to the object, the angular acceleration is A uniform rod of length l= 2.5 m can pivot freely about a hinge attached to a wall like in the figure. The rod is held horizontally and then it is released. Determine the angular acceleration of the rod. A centrifuge rotor bas a moment of inertia of 400 kg m2. How much energy is required to bring it from rest to 375 rpm?Explanation / Answer
1) torque = I x alpha
2.5 = 1.25 alpha
alpha = 2 rad/s2
2) torque = I x alpha
mg x 2.5 /2 = m x 2.5^2 /3 x alpha
alpha = 5.88 rad/s2 so 5.9 rad/s2
3) K.E+ R.E = mv^2 /2 + Iw^2/2
100 x 5^2 /2 + (2 x 100 x R^2 /5) x (5/R)^2 /2
= 1750 J
4) w = 375 rpm = 375 x 2 pi / 60 =39.27 rad/s
work done= Iw^2 /2 = 400 x 39.27^2 /2 = 3.1 x 10^5 J
5) torque = r x F
= rFcos(theta)
so image 1 .
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