A point charge of -9.00x10^-9 C is located at the point (x,y) = (0,3) meters on

Question

A point charge of -9.00x10^-9 C is located at the point (x,y) = (0,3) meters on the y-axis, while a second point charge of +6.00x10^-9 C is located at the point (x,y) = (4,0) meters on the x-axis.

(a) Calculate the total electric field (magnitude and direction) that these point charges generate at the origin of the xy-coordinate system.

(b) A third point charge of -2.00x10^-9 C is now placed at the origin of the xy-coordinate system while keeping the first two point charges fixed at their original positions. Calculate the net electric force (magnitude and direction) exerted by the two point charges on the third charge.

Explanation / Answer

a) q1 creates a field to the left and q2 creates a to the right. So their fields will subtract E = k*(q2/r2^2 - q1/r1^2) = 9.0x10^9*(6.00x10^-9/0.09^2 - 8.0x10^-9/0.16^2) = 3850N/C so answer is (3850,0)N/C b) Now both fields point to the left so E = 9.0x10^9*(-6.00x10^-9/0.09^2 - 8.0x10^-9/0.16^2) = -9480N/C so answer is (-9480,0)N/C

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