Take element Z = 36 from the periodic table. Ionize it 35 times so that there is

Question

Take element Z = 36 from the periodic table. Ionize it 35 times so that there is only one electron left orbiting around the nucleus. What is the ground state energy of the electron?
I figured out the answer to be -1.76*10^4 eV
Please help me on the second part!
What is the energy of the electron when it is in the n = 14 principal state in the ion above?

Explanation / Answer

The energy of an electron in nth state En is given by: En = KE + PE En = 1/2 mv2 + (– KZe2 / rn) = –1/2 KZe2 / rn => En = –2p2K2e4Z2 / n2h2 (putting value of rn) = –2.178 × 10–18 Z2/n2 J / atom = –13.6 Z2/n2 eV = –1312 Z^2/n^2 kJ/mol substituting the values of Z and n, we get , En = 89.92 eV.

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