Take element Z = 48 from the periodic table. Ionize it 47 times so that there is
ID: 2104289 • Letter: T
Question
Take element Z = 48 from the periodic table. Ionize it 47 times so that there is only one electron left orbiting around the nucleus. What is the ground state energy of the electron?
What is the energy of the electron when it is in the n = 11 principal state in the ion above?
Take element Z = 48 from the periodic table. Ionize it 47 times so that there is only one electron left orbiting around the nucleus. What is the ground state energy of the electron?
What is the energy of the electron when it is in the n = 11 principal state in the ion above?
Explanation / Answer
energy=-13.6*Z^2/n^2
=-13.6*48^2/11^2
=-258.962 eV
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