A string of mass 60 grams and length 7.5m is fixed at both ends. The string has

Question

A string of mass 60 grams and length 7.5m is fixed at both ends. The string has a tension of 88N and vibrates with a total of six nodes. The maximum amplitude of the resultant standing wave for this harmonic is 9cm.
Using SI units, write a complete expression for the displacement (y) of the string as a function of position (x) and time (t). (Yo may assume the left end of the string is at x = 0).

i got: y(x,t) = (0.09m) sin (2.09N/m)x cos(5.9rad/s)t

what did i do wrong? please provide a step by step on how to solve this

Explanation / Answer

=2*7.5/6=2.5 m

velocity=T/(m/l) =104.88

f=104.88/2.5=41.95, k=2/=2.51

=2f=263.57

y(x,t) = (0.09m) sin kx cost

y(x,t) = (0.09m) sin 2.51x cos263..51t

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