A string is wrapped around a disk of mass m = 1.6 kg and radius R = 0.12 m. Star

Question

A string is wrapped around a disk of mass m = 1.6 kg and radius R = 0.12 m. Starting from rest, you pull the string with a constant force F = 6 N along a nearly frictionless surface. At the instant when the center of the disk has moved a distance x = 0.16 m, your hand has moved a distance of d = 0.26 m.

(a) At this instant, what is the speed of the center of mass of the disk?
vcm = 1.095   m/s (this part was solved)
(b) At this instant, how much rotational kinetic energy does the disk have relative to its center of mass?
Krot =   J (i want this part to be solve)

Explanation / Answer

delta E sys = W surr, real
delta K trans + delta K rot = F (x + d)
delta K rot = F(x + d) - Fx

=6*(0.16+0.26)-6*0.16

=1.56 J

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