At an air show, a jet plane has velocity components Vx = 720km/h and Vy = 465km/

Question

At an air show, a jet plane has velocity components Vx = 720km/h and Vy = 465km/h at time 4.80s and Vx= 888 and Vy = 450 at time 6.72.

part A) For this time interval, find the x component of the plane's average acceleration. (km/h^2)

part B) For this time interval, find the y component of the plane's average acceleration. (Km/h^2)

Part C) For this time interval, find the magnitude of its average acceleration.

Part D) For this time interval, find the direction of its average acceleration.

Please explain how to solve these problems!! please!

Explanation / Answer

A) (888-720)/6.72 = 25 ... take Vx final - Vx initial divided by time B) (450-465)/6.72 = -2.23 ... take Vy final - Vy initial divided by time C) sqrt(25^2 + 2.23^2) = 25.1 ... take the vector sum of the Vx and Vy D) arc tan(2.23/25) = 5 degrees south of horizontal... vector angle

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