At an air show, a jet plane has velocity components v x = 655 k m / h and v y =

Question

                    At an air show, a jet plane has velocity components vx = 655km/h and vy = 415km/h at time                     4.20s and vx = 933km/h and vy = 375km/h at time 6.97s .
                

                    1. For this time interval, find the x component of the plane's average acceleration.
                

                    2. For this time interval, find the y component of the plane's average acceleration.                 

                    3. For this time interval, find the magnitude of its average acceleration.                 

                    4. For this time interval, find the direction of its average acceleration.                 

Explanation / Answer

Vi= 655i+415j

Vf=933i+375j

vf=vi+2at

a= vf-vi/2t

=(933i+375j-( 655i+415j))*5/18/6.97-4.20

=(278i-40j)*5/18/2.77

=(100.36i-14.44j)*5/18

average acceleration= (integral of adt)/(integral of dt) = a= (100.36i-14.44j)*5/18

1) x comp 27.87 m/s^2

2)y comp 9.05 m/s^2

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