A ray of light passes through a pane of glass which is 1.0 cm thick. The index o

Question

A ray of light passes through a pane of glass which is 1.0 cm thick. The index of refraction of the glass is 1.53. The angle between the normal to the surface of the pane and the ray in the air as it enters the pane is 30?. (a) Find the angle (degrees) between the normal to the surface of the pane and the ray inside the glass. (b) Find the angle (degrees) between the normal to the surface of the pane and the ray in the air after it exits the pane.

Explanation / Answer

a> angle of reflection r = sin inverse [ sin(30) / 1.53] = sin inverse [0.3268] = 19.1 degrees b> angle of emergence = angle of incidence = 30 degrees

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