A 56.5-kg skateboarder starts out with a speed of 1.87 m/s. He does 116 J of wor

Question

A 56.5-kg skateboarder starts out with a speed of 1.87 m/s. He does 116 J of work on himself by pushing with his feet against the ground. In addition, friction does -201 J of work on him. In both cases, the forces doing the work are non-conservative. The final speed of the skateboarder is 9.40 m/s. (a) Calculate the change (PEf - PE0) in the gravitational potential energy. (b) How much has the vertical height of the skater changed? Give the absolute value.

(a) Number ? Units ?
(b) Number ? Units ?

Explanation / Answer

-delta(PE) -201 +116 = 0.5 * 56.5 *( 9.4^2- 1.87^2) delta(PE) = -2482.38 J b) delta(h) = 4.48 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.