\"I shot an arrow into the air It fell to earth, I knew not where\".............
ID: 2172363 • Letter: #
Question
"I shot an arrow into the airIt fell to earth, I knew not where"............. Henry Wadsworth Longfellow
Longfellow obviously did not learn projectile motion well. Help him out. The arrow left the bow with an initial velocity of 12.0 m/s and was launched at an angle of 35 ? above the horizontal. resistance.Assume that the arrow was launched from ground level, and neglect air (Use g = 9.80 m/s2)
a)(1 point)Find the horizontal and vertical components of the initial velocity. ___________________
b)(1 point)What is the magnitude of the arrow velocity at the highest point of its trajectory?
c)How far from the launch postion does the arrow fall to the ground?
Explanation / Answer
a) Ux = 12*cos35 = 9.83 m/s Uy = 12*sin35 = 6.88 m/s b) magnitude of velocity at heighest point = 9.83 m/s c) horizontal distance = 2 *6.88* 9.83 / 9.8 = 13.8 m
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