A hawk flies in a horizontal arc of radius 11.3 m at a constant speed of 5.7 m/s

Question

A hawk flies in a horizontal arc of radius
11.3 m at a constant speed of 5.7 m/s.
Find its centripetal acceleration.
Answer in units of m/s2

part 2
It continues to fly along the same horizon-
tal arc but increases its speed at the rate of
1.34 m/s2.Find the magnitude of acceleration under
these new conditions.
Answer in units of m/s2

part 3
Find the direction of acceleration relative to
the direction of motion under these condi-
tions. Answer between ?180(degrees) and 180(degrees).
Answer in units of degrees.

Explanation / Answer

part 1 5.7^2/11.3 = 2.87m/s^2 part2 The trick here is that they want the answer for just after the acceleration starts; the speed is still 5.7 m/s, and the radial a = 2.87. The tangential a is given as 1.34 m/s², so just add the 2 vectors: part 3 Atot = v[2.87² + 1.34²] = 3.15 m/s²

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.