In the figure, a cord runs around two massless, frictionless pulleys. A canister

Question

In the figure, a cord runs around two massless, frictionless pulleys. A canister with mass m = 37 kg hangs from one pulley, and you exert a force F rightarrow on the free end of the cord, (a) What must be the magnitude of F rightarrow if you are to lift the canister at a constant speed? (b) To lift the canister by 4.4 cm, how far must you pull the free end of the cord? During that lift, what is the work done on the canister by (c) your force (via the cord) and (d) the gravitational force? (Hint: When a cord loops around a pulley as shown, it pulls on the pulley with a net force that is twice the tension in the cord.) Number Units Number Units Number Units Number Units

Explanation / Answer

2*T = m*g T = 26*9.8/2 = 127.4 N b) To lift the canister by 3.3 cm ,we have to pull 6.6 cm of the cord. c) W =2* T*d = 2*127.14*6.6/100 =16.78 J d) W_g = m*g*3.3/100 = - 8.39 J

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.