Consider a diving board which is mounted on a hinge at one end, so it can rotate

Question

Consider a diving board which is mounted on a hinge at one end, so it can rotate about the hinge, which is the axis of rotation. To keep the board horizontal, there is a support bar located 0.75m from the hinged end of the board. The board has a mass of 60 kg and is 3.0m long, and is a uniform beam, so the center og gravity is at the center of board, 1.5 m away from each end. Calculate the force, at the hinged end, which is required to have static equilibrium? STEP BY STEP. i know it isn't hard but cant find how to do it.

Explanation / Answer

moment about hinge is zero 60 *9.8* 1.5 = F * 0.75 ( F due to support Bar) F= 1176 N equilbrium of forces R + 1176 = 588 ( R is reaction force from hinge) R = - 588 N force at hinged end is 588 N

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