A geneticist discovered a new species of insect with very long antennae. He perf

Question

A geneticist discovered a new species of insect with very long antennae. He performed the following cross (Bb x bb) and counted the number of offspring with different antennae lengths. He was unsure if his observations matched what he expected to see, so he performed a chi- squared goodness of fit test and calculated X2-4.01. If the degrees of freedom are 1, what range of p-values does his X fall between? Table 3.4 Critical values of the x distribution df 995 0.000 0.010 3 0.072 0.207 0.975 0.000 0.051 0.216 0.484 0.9 0.016 0.211 0.584 1.064 0.1 2.706 4.605 0.05 3.841 5.991 7.815 9.488 0.025 5.024 7.378 9.348 11.143 0.01 6.635 9.210 11.345 3.277 1 0.005 7.879 10.597 12.838 14.860 0.5 0.455 1.386 2.3666.251 3.357 2 7.779 0.9 x2> 0.5 0.5 >x2>0.1 0.05> x2 0.025 0.1 >x2> 0.0s ?? 0.025 > X > 0.01

Explanation / Answer

As we can see from the Chi-square value for different P-value for 1 degree of freedom, 4.01 is ranging between 0.05 and 0.25. So answer is option C which is 0.05>X2>0.025

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