A geneticist discovered a new species of insect with variable antennae length. H

Question

A geneticist discovered a new species of insect with variable antennae length. He performed the following cross (Bb x bb) and counted the number of offspring with different antennae lengths. He was unsure if his observations matched what he expected to see, so he performed a chi-squared goodness of fit test and calculated X2 - 0.281. If only two phenotypes were possible, can he reject the null hypothesis? Table 3.4 Critical values of the x distribution M 5.991 0.025 5.024 7.378 9.348 11.143 0.01 6.635 9.210 11.345 13.277 0.005 7.879 10.597 12.838 14.860 0.995 0.975 0.9 0.5 0.1 0.05 0.000 0.000 0.0160.455 2.706 3.841 0.010 0.051 0.211 1 .386 4.605 0.072 0.216 0.584 2.3666.251 7.815 0.207 0.484 1.064 3.357 7.779 9.488 O No. P0.05 so any difference seen was not due to chance. O Yes. P >0.05 so any difference seen was due to chance. O No. P >0.05 so any difference seen was not due to chance. O Yes. P

Explanation / Answer

Ans.

The calculated value of Chi square is less than the table value, the deviations of the observed data from expected frequencies are accepted purely due to chance. Therefore, the null hypothesis is accepted, and it is concluded that the observed data are in accordance with the expected ratio.

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