A geneticist discovered a new species of insect with variable antennae length. H

Question

A geneticist discovered a new species of insect with variable antennae length. He performed the following cross (Bb x bb)and counted the number of offspring with different antennae lengths. He was unsure if his observations matched what he expected to see, so he performed a chi-squared goodness of fit test and calculated X 0.281. If only two phenotypes were possible, can he reject the null hypothesis? Table 3.4 Critical values of the x2 distribution df 0.995 0.1 0.975 0.000 0.051 0.216 0.484 0.5 0.05 0.01 6.635 9.210 11.345 1.143 13.277 14860 0.9 0.025 0.005 .016 0.455 2.706 3.84 0.211 0.000 2 0.010 3 0.072 4 0.207 1.386 4.605 0.584 2.366 6.251 1.064 3.357 7.779 5.991 7.815 9.488 5.024 7.378 9.348 .879 10.597 12.838 P>0.05 so any difference seen was due to chance Yes. P 0.05 so any difference seen was not due to chance Yes. P

Explanation / Answer

Ans- as stated chi square value is 0.281 which is greater than the considered value (0.05 generally considered to compare the chi square value ) so according to rules the hypothesis can be rejected.

As this much value show a greater errors so the hypothesis must be rejected.

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